Composition for elements

Table 1: Copper Gluconate Formula Data Mass(g) of Mass (g) of copper Gluconate wrapper Mass (g) of wrapper + Cu Mass (g) of Cu Mass (g) of gluconate 1g 2.6g 0.1g 0.9g 2.5g (show all work to receive credit)Moles of Cu recovered 0.1gCu=63.546 g/mol0.1g/63.546 g/mol = 1.5×10-3 mol Moles of Gluconate0.9 g Gluconate (C12H22O14)C=12.0107 g/mol X 12= 144.1284 g/molH= 1.008 g/mol X 22= 22.176 g/molO= 15.999X14=223.986 g/mol144.1284+22.1760+223.986= 390.29 g/mol0.9g X 1mol /390.29 g/mol = 2.3×10-3 mol Experimental Chemical Formula Cu(copper) mol Gluconate molCu(0.00113/0.00113) Gluconate 0.00220/0.00133= Cu1 Gluconate2Formula Cu(c6H11O7)2 Post-lab

Questions

1. List two sources of error in the experiment and explain the impact they had on the results. I feel two sources of error in this experiment are if you are poor at math(which I am and have spent several hours on this lab). You could also misuse the scale and not zero it and thus skew your weights and get poor results. The copper was extremely hard to handle and I and if you used anything besides the provided stir rod you can take copper from your solution by it getting on gloves and other things.

2. Using your own lab results, calculate the percent composition for each element in the compound copper gluconate. Clearly label each element and the percentage. You must show all work (not just the formula) to receive credit. Cu 13.9% H 4.9% C 31.8% O 49.4%

This is a sample question

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